\( 2 = e^{200k} \Rightarrow k = \frac{\ln 2}{200} \)
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- #### 45:154
- \( P(-800) = P_0 \cdot e^{(\ln 2 / 200)(-800)} = P_0 \cdot e^{-4\ln 2} = P_0 \cdot (e^{\ln 2})^{-4} = P_0 \cdot 2^{-4} = P_0 / 16 \)
- \( 30^{0.7} = e^{0.7 \ln 30} \approx e^{0.7 \cdot 3.4012} = e^{2.3808} \approx 10.81 \)
- \( Q_1 = 50 \cdot 10.81 = 540.5 \)
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