-4y \leq -60 \\

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• 3(50 - 2y) + 2y \leq 90 \\
• - 6y + 2y \leq 90 \\
• - 4y \leq 90 \\
• y \geq 15
• Si \( y = 15 \), alors \( x = 50 - 2(15) = 20 \).
• Donc, la production maximale sans dépasser les ressources est \( x = 20 \), \( y = 15 \).

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