Minimum length for 3 non-adjacent G’s: G _ G _ G → 5 positions. Only one such configuration up to shift: G G G with gaps — actually, only possible if they are in positions with separation.
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- Try: placing 3 G’s with no two adjacent in 5 positions.
- Let the G’s occupy 3 positions such that no two are adjacent.
- Then gaps: between G’s must be at least one non-G.
- Positions: must satisfy $ g_2 \ge g_1 + 2 $, $ g_3 \ge g_2 + 2 $. The minimal span is 5: e.g., 1,3,5.
- Only one such triplet of positions in 8? No — multiple.
- But we already fixed C’s, and the 5 free positions are a subset of the 8, not consecutive.
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