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CSDN PATCSDN C PAT
PATPAT PAT PAT.
Kevin pat9020 20min.
2022 PAT & PATFEE 2022 3 5 13:30-16:30 .
PAT 100 345 .
PAT PATPAT& PAT PAT2.
PAT
PAT 100 5~6 :-) 60 .
ACMerpat.pat,GG (..);,patACM.
PAT PAT2020 1.3%offer1795 200offer 9: 1 .
ight) - 10 = 2(5 - \sqrt{7}) - 10 = -2\sqrt{7} < 0 \quad ( ext{local maximum}).
Thus, the revenue growth rate is maximized at \( t = rac{5 - \sqrt{7}}{9} \).
oxed{rac{5 - \sqrt{7}}{9}}
A pharmacologist is studying the concentration of a new Alzheimer's drug in the bloodstream, modeled by the function \( C(x) = 5x^2e^{-x} \). Determine the dosage level \( x \) that maximizes the concentration.
To find the dosage level that maximizes the concentration, we first find the derivative of \( C(x) \):
C'(x) = rac{d}{dx}(5x^2e^{-x}).
Using the product rule, where \( u = 5x^2 \) and \( v = e^{-x} \), we have:
C'(x) = u'v + uv' = (10x)e^{-x} + 5x^2(-e^{-x}) = e^{-x}(10x - 5x^2).
Set \( C'(x) = 0 \) to find critical points:
e^{-x}(10x - 5x^2) = 0.