Primero, enumeramos los pares de factores de $12$:
**Primero, enumer
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- eq 2$, cela se simplifie en $a-2 = 5$.
- + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 = 285
- Adicionalmente, consideramos los divisores negativos:
- Cada par positivo y su contraparte correspondiente negativa da dos soluciones (una donde ambos factores son positivos y otra donde ambos son negativos).
- Los pares de factores enteros de $12$ son:
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