Home / We need 18n = multiple of 45 → n divisible by 5/ gcd(2,5)=5 → n multiple of 5? Actually: 18n divisible by 45 → n divisible by 45 / gcd(18,45) = 45/9 = 5 → yes, n divisible by 5.

We need 18n = multiple of 45 → n divisible by 5/ gcd(2,5)=5 → n multiple of 5? Actually: 18n divisible by 45 → n divisible by 45 / gcd(18,45) = 45/9 = 5 → yes, n divisible by 5.

February 22, 2026

Wait: 18n divisible by 45 → 2n divisible by 5 → n divisible by 5. So every valid n must make step count a multiple of 5.
But multiples of 5 give angles divisible by 90 (45×5=225 → divisible by 45 but 225 ÷ 90 = 2.5 → no).
Wait: 45×5 = 225 → 225 ÷ 18 = 12.5 → not integer.
So smallest n = 5 → angle = 18×5 = 90° → multiple of 90 → invalid.
Next: n = 10 → 180° → multiple of 90 → invalid.
n = 15 → 270° → 270 ÷ 90 = 3 → invalid.