x^3 + y^3 = (x + y)^3 - 3xy(x + y) = 10^3 - 3 \cdot 21 \cdot 10 = 1000 - 630 = 370

x^3 + y^3 = (x + y)^3 - 3xy(x + y) = 10^3 - 3 \cdot 21 \cdot 10 = 1000 - 630 = 370

Understanding the Identity: x³ + y³ = (x + y)³ − 3xy(x + y) Applied to a Numerical Proof


Unlocking the Power of Algebraic Identities: A Deep Dive into x³ + y³ = (x + y)³ − 3xy(x + y)

Mathematics is filled with elegant identities that simplify complex expressions and reveal hidden patterns. One such powerful identity is:

x³ + y³ = (x + y)³ − 3xy(x + y)

This formula is not only foundational in algebra but also incredibly useful for solving equations involving cubes — especially when numerical substitutions are involved.


What is the Identity?

The identity x³ + y³ = (x + y)³ − 3xy(x + y) expresses the sum of two cubes in terms of a binomial cube minus a product-dependent correction term. This identity allows us to expand and simplify cubic expressions efficiently, particularly when factoring or evaluating expressions numerically.


Breaking Down the Formula

Start with the right-hand side:

  1. Expand (x + y)³ using the binomial theorem: (x + y)³ = x³ + y³ + 3xy(x + y)

  2. Rearranging to isolate x³ + y³, we get: x³ + y³ = (x + y)³ − 3xy(x + y)

This equation forms the basis for simplifying expressions involving cubes without direct expansion.


A Practical Numerical Illustration

Let’s apply this identity to a concrete example:

Given: x = 10, y = 21

Our goal: Evaluate the expression x³ + y³ using the identity x³ + y³ = (x + y)³ − 3xy(x + y), then verify it equals 370.


Step 1: Plug in the values

  • x = 10, y = 21
  • x + y = 31
  • xy = 10 × 21 = 210

Step 2: Apply the identity

x³ + y³ = (x + y)³ − 3xy(x + y) = (31)³ − 3(210)(31)

Calculate each term:

  • (31)³ = 29791
  • 3 × 210 × 31 = 630 × 31 = 19530

Now subtract: 29791 − 19530 = 10261

Wait — this result (10261) doesn’t match the claimed 370. Let’s double-check our target.


Reconciling the Claim: x³ + y³ = 10³ − 3·21·10

From the prompt: The expression begins as x³ + y³ = (x + y)³ − 3xy(x + y) = 10³ − 3·21·10

So let’s compute:

  • 10³ = 1000
  • 3 × 21 × 10 = 630
  • 1000 − 630 = 370

This matches a known identity form, but it does not directly result from expanding x³ + y³ — rather, it's a partial forward evaluation with strategic substitution.

In fact, x = 10, y = 21:

  • x³ = 1000
  • y³ = 21³ = 9261
  • So x³ + y³ = 1000 + 9261 = 10261

Then: (10 + 21)³ = 31³ = 29791 3xy(x + y) = 3 × 210 × 31 = 19530 So (x + y)³ − 3xy(x + y) = 29791 − 19530 = 10261, consistent above.

Thus, x³ + y³ = 10261, not 370.


But Wait — Where Does 370 Come From?

There appears to be a numerical discrepancy. However, if the target is x³ + y³ = 10³ − 3·xy·10, re-evaluating:

Assume the original problem intended:

x = 10, y = ? such that x³ + y³ = 10³ − 3·xy·10 = 1000 − 30xy

But substituting y = 21 gives: 1000 − 630 = 370, which matches 10³ − 3·10·21 = 1000 − 630 = 370 — but this reflects a non-symmetric scenario.

Let’s solve algebraically:

Suppose x³ + y³ = 10³ − 3xy·10

Then using the identity: x³ + y³ = (x + y)³ − 3xy(x + y)

So: (x + y)³ − 3xy(x + y) = 1000 − 30xy

Rearranging: (x + y)³ − 3xy(x + y) + 30xy = 1000

This is a constrained equation, but not standard.


Conclusion: The Identity’s Power and Numerical Insight

The identity x³ + y³ = (x + y)³ − 3xy(x + y) is a cornerstone of algebraic manipulation, especially useful for expanding cubes quickly and factoring expressions.

While the direct substitution x = 10, y = 21 yields x³ + y³ = 10261, the reduced value 370 arises from a specific subtraction: 10³ − 3·xy·10 = 1000 − 630 = 370

This example illustrates how algebraic identities enable fast evaluation — even if full expansions give larger results, smart decomposition helps simplify complex calculations.


Key Takeaways

  • The identity x³ + y³ = (x + y)³ − 3xy(x + y) is essential for efficient cubic expansions.
  • Number substitutions simplify evaluation and verification.
  • Always cross-check results, as discrepancies can arise from misapplied contexts or miscalculations.
  • Understanding identities unlocks deeper insight into algebraic structures and problem-solving.

Ready to apply this identity in your homework or real-world calculations? Use it to expand cubes, simplify expressions, and solve problems faster.


Keywords: x³ + y³ identity, algebraic simplification, (x + y)³ expansion, 3xy(x + y), numerical verification, math identity, algebra practical application, cubic equations, math tutorial, finite mathematics.


Want more? Explore how to solve advanced equations using cubic identities — optimize your math toolkit today!

Related Articles

Trending Articles